<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The radius of the base of a cone is 4 inches. The slant height of the cone is 6 inches. Which is closest to the surface area of the cone ?
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
Radius (r) of the base of a cone is 4 inches.
Slant height (l) of the cone is 6 inches.
<h3>To Find:-</h3>
Which is closest to the surface area of the cone ?
<h2>Solution:-</h2>
We know,
Formula of surface area of a cone is πr(r + l) sq. units.
Taking value of π = 3.14
So, Surface area of the cone = 3.14 × 4(4 + 6)
Surface area of the cone = 12.56 × 10
Surface area of the cone = 125.6 sq. inches.
126 sq. inches is closest to 125.6 sq. inches.
So, option (H) <u>1</u><u>2</u><u>6</u><u> </u><u>s</u><u>q</u><u>.</u><u> </u><u>i</u><u>n</u> is correct. [Answer]
Answer:
2,5 and 2,7 I believe
Step-by-step explanation:
It should be 2,5 and 2,7
Answer:
2
Step-by-step explanation:
2x + 4 = 8
subtract 4 from both sides
2x = 4
divide by 2
x = 2
Answer:
Step-by-step explanation:
This is where your <em>median</em> is near the lower quartile.
I am joyous to assist you anytime.