We can use the subtraction property of logs to expand the right side of the equation:
log(1/H*) = log(1) - log(H*)
No matter what base we’re using, log(1) = 0, so this simplifies to -log(H*). We’re also given a pH value of 3.6, so we can substitute this value into the original equation along with -log(H*) to get
3.6 = -log(H*)
Multiplying by -1 on both sides:
-3.6 = log(H*)
And rewriting in exponential form:
H* = 10^(-3.6) = 0.0003 (rounded to the nearest ten thousandth)
<span>|c^2 + b^2|
=</span><span>|(-2)^2 + (-3)^2|
=</span><span>|4 + 9|
=13
answer is </span><span>D.13</span>
Answer:
x=-16
Step-by-step explanation:
6x - 2y = 14
-7x + 2y = 2
−10+1≤3x≤1+1
2 Simplify.
−9≤3x≤2
3 Divide the whole equation by 3.
9/3 ≤x≤ 2/3
4 Simplify.
−3≤x≤ 2/3
-3<x<4
