3 years ago

Please please please help

Mathematics

1 answer:

rusak2 [61]3 years ago

4 0

What i See Is 2 Over -5

You might be interested in

A rectangular patio has a length of 12 1/2 feet and an area of 108 1/8 square feet what is the width of the patio

Ivenika [448]

Length of the rectangular patio = $12\frac{1}{2}=\frac{25}{2}$

Let the width of the patio be = x

Area of the patio is given as = $108\frac{1}{8}=\frac{865}{8}$

As the area of a rectangle is = length*width, so

$\frac{865}{8}=(\frac{25}{2})x$

$\frac{865}{8}*\frac{2}{25}=x$

x= $\frac{1730}{200}$ = $\frac{173}{20}$

x = $8\frac{13}{20}$

Hence, width of the patio is $8\frac{13}{20}$ feet.

7 0

4 years ago

One end of a ladder 32 feet long is placed 10 feet from the outer wall of a building that stands on the ground level. How far up

ladessa [460]

Answer:

30 ft

Step-by-step explanation:

This is a classic right triangle problem, where the length of the ladder represents the hypotenuse, where the ladder is lengthwise from the building is the base of the triangle, and what we are looking for is the height of the triangle. Pythagorean's Theorem will help us find this length.

$32^2-10^2=y^2$ so