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2 years ago

Help .............................................

Mathematics

1 answer:

mario62 [17]2 years ago

5 0

In order to get our answer, all we need to do is multiply the speed by the time.

$3* 10^{8} *3.15* 10^{7} = 9.45* 10^{15}$

So, our answer is: $9.45* 10^{15} meters$

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Y = 2x + 7<br> a) Work out the value of y when x=4<br> b) Work out the value of y when x=-3

creativ13 [48]

A ) y = 2(3) + 7
y = 15

b ) y = 2(-3) + 7
y = 1

6 0

2 years ago

In triangle abc, AC=15 BC=11 and m

Oksana_A [137]

Answer: 10

Step-by-step explanation:

In a right angle triangle

Hypothenus ^2= opposite ^2+ adjacent ^2

According to a diagram below

Hypothenus =15

Opposite =?

Adjacent =11

Substitute for the values

15^2=11^2+opp^2

Opp^2=15^2-11^2

0pp^2= 225-121

Opp2=104

Opp= square root of 104

Opp= 10.2

Opp= ~10

3 0

3 years ago

A group of preschoolers has 8boys and 24 girls. What is the ratio of girls to all children

Zepler [3.9K]

The total number of kids:
8+24 = 32
the ratio is 24:32
it simplifies into 3:4

5 0

2 years ago

Read 2 more answers

Find the inverse of f(x)=-3x+3

kolezko [41]

To get the inverse, first off do a quick switch on the variables, and then solve for "y".

$\bf f(x)=y=-3x+3\qquad \qquad inverse\implies \boxed{x}=-3\boxed{y}+3
\\\\\\
x-3=-3y\implies \cfrac{x-3}{-3}=y\implies \cfrac{3-x}{3}=y\impliedby f^{-1}(x)$

5 0

2 years ago

5 points

jonny [76]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$y = \stackrel{\stackrel{m}{\downarrow }}{2}x-5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 2 and passes through (4 , -3)

$(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y+3=2x-8\implies y=2x-11$

5 0

2 years ago