Enter an inequality that represents the graph in the box.PLEASE HELP ME!

Mathematics

2 answers:

a_sh-v [17]3 years ago

7 0

The line is solid so we have either ≤ or ≥

find the equation of the line

ok, a y intercept if -1
sllope=rise/run=3/1=3

y=mx+b
m=slope
b=y intercept

y=3x-1 is the equaton

now find if it's y≥3x-1 or y≤3x-1

test a point
we see (0,0) Is not in in it
test it in y≥3x-1
0≥3(0)-1
0≥-1
false,
so this is the equation because (0,0) is not a valid solution for this equation

answer is y≥3x-1

Tasya [4]3 years ago

5 0

its actually y=>3x-1 because it's shaded below the line.

below the line: < or <=

above the line: > or>=

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(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$