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irinina [24]
3 years ago
7

Simplify the expressions to develop a rule for multiplying powers with the same base. (Help!!)

Mathematics
1 answer:
Mazyrski [523]3 years ago
8 0

2².2³=2²⁺³=2⁵=32

4³.4=4³⁺¹=4⁴=256

3.3²=3¹⁺²=3³=27

x².x³=x²⁺³=x⁵

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. Toby invested £4500 for 2 years in a savings account. He was paid 4% per annum COMPOUND
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Answer:

£4867.2

Step-by-step explanation:

Given data

P= £4500

T=2 years

R= 4%

The compound interest expression

A=P(1+r)^t

substitute

A= 4500(1+0.04)^2

A=4500(1.04)^2

A=4500*1.0816

A=£4867.2

Hence the balance is £4867.2

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3 years ago
What is Answer<br> 1/5 + 1/3 + 1/4
Lady bird [3.3K]

Answer:

12/60+20/60+15/60=47/60

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If x - 2y + z = 5 and -x + 3y - z = 2, then y = ?
jok3333 [9.3K]

Answer:

y=10

Step-by-step explanation:

5 0
3 years ago
Sally is standing at one corner of a snowy rectangular field that measures 200 ft by 200 ft. She wishes toreach a warm cabin loc
pshichka [43]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The optimal point(i.e the position of  P) that will allow Sally to reach the cabin as quickly as possible is  d =  50 \ ft from the cabin.

Step-by-step explanation:

From the question we are told that

   The speed from the point Sally is standing to the point P is  u =  3 \  ft /s

   The speed from the point P to the cabin is v  =  5 \  ft /s

   

Let denote the distance from the bottom left corner to the  P  be  y  ft

 Generally according to Pythagoras theorem the distance from Sally's first position to point P is mathematically represented as

          s = \sqrt{y^2 + 200^2}

Generally the distance from that point P to the cabin is mathematically represented as

       d =  200 -y

Generally the time it takes Sally to cover that distance s is mathematically represented as

       t_1 =  \frac{s}{u}

=>     t_1 =  \frac{ \sqrt{y^2 + 200^2}}{3}

Generally the time it takes Sally to cover that distance d is mathematically represented as

       t_2 =  \frac{d}{v}

=>     t_2 =  \frac{ 200 - y }{5}

So the total time taken is  

        t= \frac{ \sqrt{y^2 + 200^2}}{3}  +  \frac{ 200 - y }{5}

Generally the minimum time taken with respect to the distance is mathematically evaluated by differentiating and equating the derivative to 0

So  

     \frac{dt}{dy} =\frac{1}{3} \frac{y}{ \sqrt{y^2 + 200^2} }  -  \frac{1}{5}  =0      

=> \frac{dt}{dy} = \frac{y^2 }{y^2 + 200 ^2} =\frac{9}{25}

=> 25y^2 = 9y^2 + 9 * 200^2        

=> 16y^2 = 360000          

=> y = 150

So the distance from point P to the cabin is  

           d =  200 -150

=>       d =  50 \ ft

So  the optimal point(i.e the position of  P) that will allow Sally to reach the cabin as quickly as possible is  d =  50 \ ft from the cabin

       

8 0
2 years ago
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