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oksian1 [2.3K]
3 years ago
11

A human body that is performing light work generates about 400 btus of the body heat per hour while active. if an office that is

20 ft x 30ft x 10ft has 8 workers, how many btus per cubic foot do they produce in 3 hours(to the nearest tenth)
A)0.2 BTUs/ft3
B)0.6
C)1.5
D)2.9
Mathematics
1 answer:
Neporo4naja [7]3 years ago
6 0
I got none of the above my answer is 1.6 BTUs/ft3. I did 400 x 8 x 3 for total BTUs = 9600 btus and the volume of the room was 20 x 30 x10 ft = 6000 cu ft so 9600/6000= 1.6 BTUs/ft3
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A "planet transit" is a rare celestial event in which a planet appears to cross in front of its star as seen from Earth. The pla
nikitadnepr [17]

Answer:

There is a 55.95% probability that, in the next 3,000 stars monitored by the Kepler mission, more than 4 planet transits will be seen.

Step-by-step explanation:

Assume that the number of planet transits discovered for every 3,000 stars follows a Poisson distribution with λ=5.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\lambda is the mean in the given time interval.

For this problem, we have that \lambda = 5

What is the probability that, in the next 3,000 stars monitored by the Kepler mission, more than 4 planet transits will be seen?

That is P(X > 4). We either see 4 or less planets, or we see more than 4. The sum of the probabilities is decimal 1. So

P(X \leq 4) + P(X > 4) = 1

P(X > 4) = 1 - P(X \leq 4)

In which

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

So

P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}

P(X = 0) = \frac{e^{-5}*5^{0}}{(0)!} = 0.0067

P(X = 1) = \frac{e^{-5}*5^{1}}{(1)!} = 0.0337

P(X = 2) = \frac{e^{-5}*5^{2}}{(2)!} = 0.0842

P(X = 3) = \frac{e^{-5}*5^{3}}{(3)!} = 0.1404

P(X = 4) = \frac{e^{-5}*5^{4}}{(4)!} = 0.1755

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0067 + 0.0337 + 0.0842 + 0.1404 + 0.1755 = 0.4405

Finally

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.4405 = 0.5595

There is a 55.95% probability that, in the next 3,000 stars monitored by the Kepler mission, more than 4 planet transits will be seen.

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3 years ago
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Answer:

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Step-by-step explanation:

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