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3 years ago

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A human body that is performing light work generates about 400 btus of the body heat per hour while active. if an office that is

20 ft x 30ft x 10ft has 8 workers, how many btus per cubic foot do they produce in 3 hours(to the nearest tenth)
A)0.2 BTUs/ft3
B)0.6
C)1.5
D)2.9

1 answer:

Neporo4naja [7]3 years ago

6 0

I got none of the above my answer is 1.6 BTUs/ft3. I did 400 x 8 x 3 for total BTUs = 9600 btus and the volume of the room was 20 x 30 x10 ft = 6000 cu ft so 9600/6000= 1.6 BTUs/ft3

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Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

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Answer:

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Step-by-step explanation:

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The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

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$4C = 8$

$C = 2$

The solution in the form is

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$y(t) = y_{0}e^{4t} + 2$

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The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

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