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3 years ago

How do I draw a model that shows 0.16

Mathematics

2 answers:

Semmy [17]3 years ago

8 0

You would find the dimensions of the object that you are drawing then divide it by .16

Sphinxa [80]3 years ago

6 0

Here is what I would do:
1. Draw a number line from 0 to 1 that has enough room for 10 1/10 marks on the line.
2. Draw 10 marks between the 1/10 marks so that you have 100 marks between 0 and one.
3. Draw a dot on the mark that represents 0.16.

Should be done.

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4. Simplify the following using the quotient rule of exponents:

7nadin3 [17]

Answer:

31=1/1

33=1/1

30=3/10

3-=-3

Step-by-step explanation:

7 0

3 years ago

Can someone please help me with this problem? An explanation would be great, but it can be short. Thank you!!

ss7ja [257]

We are given two points: (4, -8) and (8, 5)

General equation of a line: y = mx + c

First find m (the gradient). There is a formula for this: (change in y)/(change in x) = gradient

(5 - -8) / (8 - 4) = (13) / (4) = 3.25 = m

y = 3.25x + c

Now we need to find c (the y-intercept; the value of y when x=0).

Substitute in any one of the coordinates - let's use (8, 5)

(5) = 3.25(8) + c

(5) = 26 + c

c = -21

The equation of the line: y = 3.25x - 21

I think that this answer is correct - sorry if it seems rushed.

Hope this answer helps :)

7 0

4 years ago

Joel is constructing a line perpendicular . He has already constructed three arcs as shown. Use the image to answer the question

IgorC [24]

<span>It must be the same as it was when constructing the arc above P.</span>

8 0

3 years ago

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Nathan wants to use coordinate geometry to prove that the opposite sides of a rectangle are congruent. He places parallelogram A

valentina_108 [34]

<h3><u>Answer:</u></h3>

The formula determine the distance from C to D is:

$\sqrt{(0-a)^2+(-b)^2}=\sqrt{a^2}=a$

<h3><u>Step-by-step explanation:</u></h3>

The formula that can be used to determine the distance from point C to point D is:

$\sqrt{(0-a)^2+(-b)^2}=\sqrt{a^2}=a$

We know that distance between two points A(a,b) and B(c,d) is equal to the length of the line segment AB and is calculated by the help of the formula:

$\sqrt{(c-a)^2+(b-d)^2}$

So, here we have:

(a,b)=(a,b) and (c,d)=(0,b)

3 0

3 years ago

Write an equation in slope-intercept form for the line that passes through the

Pavlova-9 [17]

Make slope intercept
3x - y = 5
3x = y + 5
y = 3x - 5
Parallel = same slope
Slope = 3
Y = 3x + b
Plug in the point
-2 = 3(-1) + b
-2 = -3 + b, b = 1

Solution: y = 3x + 1

6 0

3 years ago

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