To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
I think it is 5.67 because of the saying dkhg.....
Answer:
Step-by-step explanation:
The formula for cos θ is a/r. A is the first number (10) and b is the second number (6). R is the hypoteneuse which can be found through r = .
In the equation you'd write that as r = which can be simplified to .
You end up with and you simplify this by doing , ending with the result of .
(I also got this answer right on the test.)
Step-by-step explanation:
(4-7i)-(-3+6i)
4-7i+3-6i
7-13i(simplified)