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wariber [46]
3 years ago
15

How do you solve it with quadratic formula?

Mathematics
2 answers:
Lisa [10]3 years ago
7 0

Given:

7(x-5)^2=63

To make this easier, let's expand the left side of the equation. (x-5)^2 is the same as (x-5)(x-5). Let's rewrite it:

7(x-5)(x-5)=63

Let's use the FOIL method (First, Outer, Inner, Last) to simplify the binomial of (x-5)(x-5) on the left. We then get:

7(x^2-10x+25)=63

Distribute the seven on the left side (which means multiply the seven by everything in the parenthesis) We are left with:

7x^2-70x+175=63

Since we must have the equation set to 0 to use the quadratic formula, subtract 63 from both sides:

7x^2-70x+112=0

Now, we can use the quadratic formula. The quadratic formula is:

x=\frac{-b+\sqrt{(b)^2-4(a)(c)}}{2(a)} and x=\frac{-b-\sqrt{(b)^2-4(a)(c)}}{2(a)}

Let's identify our a, b and c values:

a: 7

b: -70

c: 112

Plug in your values into the equation:

x=\frac{70+\sqrt{(-70)^2-4(7)(112)}}{2(7)}

Simplify the value inside the square root (called the discriminant) and the denominator:

x=\frac{70+\sqrt{1764}}{14}

Simplify the square root. The square root of 1764 is 42:

x=\frac{70+42}{14}

Simplify the numerator:

x=\frac{112}{14}

Simplify:

x=8

That's just one answer, lets get the other one.

x=\frac{70-42}{14}

Simplify the numerator:

x=\frac{28}{14}

Simplify:

x=2

Your answers would be:

x=8

x=2


Dima020 [189]3 years ago
4 0
Tell me the answer is correct

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6 0
3 years ago
4y-x=5+2y; 3x+7y=24 solve systen by using substitution
jek_recluse [69]
4y - x = 5 + 2y ..... (1)
3x + 7y = 24    ..... (2)

by grouping like terms in (1)
4y - x = 5 + 2y
4y - 2y - x = 5
<span>-x + 2y = 5 </span>        ..... (1a)

by multiplying (1a) through by -3
(-3)(-x) + 2(-3)y = 5(-3)
3x  -  6y = -15  ..... (1b)

by subtracting 1a from 2
3x -3x + 7y - (-6y) = 24 - (-15)
                      13y = 39
           ⇒            y = 3

by substituting y=3 into (2)
    3x + 7(3) = 24 
              3x = 24 - 21
              3x = 3
        ⇒     x = 1


∴ solution to the system is x=1 when y = 3
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3 years ago
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3 years ago
What is the solution to the following system?
leva [86]

Answer:

(4,3,2)

Step-by-step explanation:

We can solve this via matrices, so the equations given can be written in matrix form as:

\left[\begin{array}{cccc}3&2&1&20\\1&-4&-1&-10\\2&1&2&15\end{array}\right]

Now I will shift rows to make my pivot point (top left) a 1 and so:

\left[\begin{array}{cccc}1&-4&-1&-10\\2&1&2&15\\3&2&1&20\end{array}\right]

Next I will come up with algorithms that can cancel out numbers where R1 means row 1, R2 means row 2 and R3 means row three therefore,

-2R1+R2=R2 , -3R1+R3=R3

\left[\begin{array}{cccc}1&-4&-1&-10\\0&9&4&35\\0&14&4&50\end{array}\right]

\frac{R_2}{9}=R_2


\left[\begin{array}{cccc}1&-4&-1&-10\\0&1&\frac{4}{9}&\frac{35}{9}\\0&14&4&50\end{array}\right]


4R2+R1=R1 , -14R2+R3=R3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&-\frac{20}{9}&-\frac{40}{9}\end{array}\right]


-\frac{9}{20}R_3=R_3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&1&2\end{array}\right]


-\frac{4}{9}R_3+R_2=R2 , -\frac{7}{9}R_3+R_1=R_1


\left[\begin{array}{cccc}1&0&0&4\\0&1&0&3\\0&0&1&2\end{array}\right]


Therefore the solution to the system of equations are (x,y,z) = (4,3,2)

Note: If answer choices are given, plug them in and see if you get what is "equal to".  Meaning plug in 4 for x, 3 for y and 2 for z in the first equation and you should get 20, second equation -10 and third 15.

7 0
4 years ago
If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5
Phoenix [80]
I hope this helps <span>24 = k * 6  </span><span>4 = k  </span><span>y = kx  </span><span>y = 4x  </span><span>y = 4 * 5  </span><span>y = 20 

</span>
6 0
4 years ago
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