Question

What are the solutions to the quadratic equation (5y + 6)2 = 24?

Answer 1

The correct answers would be $\frac{-6 +/- 2\sqrt{6} }{5}$

We can find this answer by first putting it into standard form. To do this we need to multiply the parenthesis and then solve for 0. 

(5y + 6)^2 = 24
25y^2 + 60y + 36 = 24
25y^2 + 60y + 12 = 0 

Now we can find the a, b and c values for the quadratic equation based on the standard form. 

a = 25 (number attached to x^2)
b = 60 (number attached to x)
c = 12 (number with no variable)

Now we use these in the quadratic equation and simplify. 

$\frac{-b +/- \sqrt{ b^{2} -4ac } }{2a}$

$\frac{-60 +/- \sqrt{ 60^{2} -4(25)(12) } }{2(25)}$

$\frac{-60 +/- \sqrt{ 2400 } }{50}$

$\frac{-6 +/- 2\sqrt{6} }{5}$

Answer 2

To solve for y, apply the distributive property:
$10y + 12 = 24$
Then, subtract 12 from both sides and you will get:
$10y = 12$
Then solve for y, by dividing both sides by 10.

Your final answer will be y=1.2