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Ymorist [56]
3 years ago
8

The perimeter of a triangle is 117 inches. If one side of the triangle is 11 more than the shorter side, and the longer side is

25 more than the shorter side, find the lengths of the three sides?
Mathematics
1 answer:
VLD [36.1K]3 years ago
6 0

Let the shorter side be x.

"one side of the triangle is 11 more than the shorter side" is x + 11

"and the longer side is 25 more than the shorter side" is x + 25


x + x + 11 + x + 25 = 117


3x + 36 = 117


3x = 81


x = 27


x + 11 = 38


x + 25 = 52


Answer: The sides have lengths 27 in., 38 in., and 52 in.

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Answer:

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​

Step-by-step explanation:

"0.3" was replaced by "(3/10)". 2 more similar replacement(s). Simplify 3/10

    61     3      

 (—— -  ——) -  (c + 1)  ≥ 0    then simplify 61/10

  10    10    

3.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

    61 - (3)                   29

————————  =  ——

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29    

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 5    

4.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  5  as the denominator :

            c + 1     (c + 1) • 5

   c + 1 =  —————  =  ———————————

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Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Rewrite the whole as a fraction using  5  as the denominator :

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   c + 1 =  —————  =  ———————————

                             1            5    

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

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                                          5                5

    24 - 5c

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      5    

 

Multiply both sides by  5  

5.2    Multiply both sides by (-1)

Flip the inequality sign since you are multiplying by a negative number

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     c-(24/5)  ≤ 0

5.4      Add  24/5  to both sides

            c ≤ 24/5

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