The masses of the oranges on sale at a farm stand are normally distributed with a mean of 239 grams and a standard deviation of
25 grams.
Enter the z-score of an orange that has a mass of 259 grams.
Update: The answer is 0.8
1 answer:
In order to calculate the z-score of a normal distribution, you need to apply the formula:
z = (o - m) / s
where:
o = observed value
m = mean
s = standard deviation
In your case:
z = (259 - 239) / 25 = 0.8
The answer is, indeed, z = 0.8
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