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aivan3 [116]
3 years ago
8

The masses of the oranges on sale at a farm stand are normally distributed with a mean of 239 grams and a standard deviation of

25 grams.
Enter the z-score of an orange that has a mass of 259 grams.

Update: The answer is 0.8
Mathematics
1 answer:
AleksAgata [21]3 years ago
4 0
In order to calculate the z-score of a normal distribution, you need to apply the formula:

z = (o - m) / s

where:
o = observed value
m = mean
s = standard deviation

In your case:

z = (259 - 239) / 25 = 0.8

The answer is, indeed, z = 0.8
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spayn [35]

Answer:

x = 2.5y

Step-by-step explanation:

If a cow can give 5 gallons of milk after eating 2 pounds of grass.

Let's consider 'x' is the number of pounds of grass it eats and 'y' is the number of gallons of milk the cow gives.

Hence,

5y = 2x

We will simplify it to get what x equal to y by dividing 2 on both side we find,

x = 2.5y

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3 years ago
The symphonic choir and the jazz choir are recording songs for an album. The album can be no more than 72 minutes long. The jazz
zimovet [89]

Answer:

The symphonic choir can record a maximum of 14 songs.

Step-by-step explanation:

We know that the album cannot be more than 72 minutes long, and the jazz choir records a total of 7 (3min) = 21  song minutes.

If we call c the number of songs the symphonic choir records , and each song is 3.5 minute long, then the song minutes for the symphonic choir are 3.5c; therefore, we have the inequality

3.5c+21\leq 72<em> (this says the song minutes for jazz choir plus song minutes for symphonic choice cannot exceed 72 minutes )</em>

We solve this inequality by subtracting 21 from both sides and then dividing by 3.5:

3.5c\leq 51

$c\leq \frac{51}{3.5} $

c\leq 14.47

The maximum integer value c can take is 14; therefore, the maximum number of songs the symphonic choir can record is 14 songs.

3 0
3 years ago
Please help me with this I will mark you Brainlist.
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What is the value of 9.05
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