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olga nikolaevna [1]
3 years ago
15

Whatcha dosnt belong. 9/20, 45/100, 45%, or 9/45

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0
9/45 doesn't belong. Every other fraction and percent = 45% 
max2010maxim [7]3 years ago
4 0
9/45 doesn't belong. Hope this helps.
You might be interested in
How do you figure out #9 and #10
Ann [662]
#9 the sum of two angles is 90 degrees, creating a right angle.

#10 the sum of the two angles is 180 because the form a supplementary angle
4 0
4 years ago
Can someone please check my answer? I really need help with this
Inessa05 [86]

Answer:

a = – 8

Step-by-step explanation:

From the question:

When P(x) = 2x³ – ax² + 4x – 4 is divided by x – 1, it gives a reminder of 10.

To obtain the value of a, we shall equate x – 1 to 0 as illustrated below:

x – 1 = 0

x = 0 + 1

x = 1

Next, we shall substitute the value of x into 2x³ – ax² + 4x – 4 and equating it to 10 as illustrated below:

2x³ – ax² + 4x – 4 = 10

x = 1

2(1)³ – a(1)² + 4(1) – 4 = 10

2 – a + 4 – 4 = 10

2 – a = 10

Collect like terms

– a = 10 – 2

– a = 8

Divide through by –1

a = – 8

Therefore, the value of a is –8.

5 0
3 years ago
A square sandbox has an area of 75 square feet. Estimate the length of one of the sides of the
horsena [70]

Answer:

8.7

Step-by-step explanation:

Since a square has equal side lengths, the formula for area is s^2, where s stands for side. Since we are given the area, s^2=75 square feet. Take the square root of both sides to get s is equivalent to the square root of 75 square feet. When this becomes a decimal, it is 8.66 feet. Since we are supposed to round to the nearest tenths, it rounds up to 8.7 feet per side length

8 0
4 years ago
A line for tickets to a Broadway show had a mean waiting time of 20 minutes with a standard deviation of 5 minutes.
andrezito [222]

Answer:

5.48% of the people in line waited for more than 28 minutes

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean waiting time of 20 minutes with a standard deviation of 5 minutes.

This means that \mu = 20, \sigma = 5

What percentage of the people in line waited for more than 28 minutes?

The proportion is 1 subtracted by the p-value of Z when X = 28. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{28 - 20}{5}

Z = 1.6

Z = 1.6 has a p-value of 0.9452.

1 - 0.9452 = 0.0548.

As a percentage:

0.0548*100% = 5.48%

5.48% of the people in line waited for more than 28 minutes

6 0
3 years ago
Given the function defined in the table below, find the average rate of
AURORKA [14]

Answer:

Average rate of change = \frac{2}{5}

Step-by-step explanation:

Average rate of change of a function 'f' in the interval a ≤ x ≤ b is given by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

We have to find the average rate of change in the interval 20 ≤ x ≤ 65

From the table attached,

f(65) = 32

f(20) = 14

Average rate of change = \frac{32-14}{65-20}

                                        = \frac{18}{45}

                                        = \frac{2}{5}

Therefore, average rate of change in the given interval is \frac{2}{5} .

7 0
3 years ago
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