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Alla [95]
4 years ago
10

A hardware store sells light bulbs in different quantities. the graph shows the cost of various quantities. according to the gra

ph, what is the cost of a single lightbulb?

Mathematics
1 answer:
skelet666 [1.2K]4 years ago
3 0

Looking at the two black dots

5 bulbs cost $9

Divide total cost by number of bulbs bought:

9 / 5 = $1.80 per bulb.

10 bulbs cost $18

Divide total cost by number of bulbs bought:

18 / 10 = $1.80 per bulb

The cost for one bulb is $1.80

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Simplifying Rational Expressions
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B^-2 / b^-3  = b^(-2-(-3) = b^1  = b

answer is d
4 0
3 years ago
A polygon is shown on a coordinate plane. The vertices are A at negative 6 comma 5, B at negative 6 comma 2, C at negative 2 com
GREYUIT [131]

Answer:

See below

Step-by-step explanation:

<u>Given a polygon with vertices</u>

  • A(-6, 5), B(-6, 2), C(-2, 2), D(-2, 6)

<u>Translation rule is</u>

  • T(5, -4)

<u>New coordinates are</u>

  • A' = (-6 + 5, 5 - 4) = (-1, 1)
  • B' = (-6 + 5, 2 - 4) = (-1, -2)
  • C' = (-2 + 5, 2 - 4) = (3, -2)
  • D' = (-2 + 5, 6 - 4) = (3, 2)

8 0
3 years ago
Question 3
Galina-37 [17]

(a) The vertical motion equation for the ball is h = 8 + 48t - 16t².

(b) The time for the ball to hit the ground is 3.15 s.

(c) The time for the ball to travel 56 ft above the ground is 0.79 s.

<h3>Vertical motion equation for the ball</h3>

The vertical motion equation for the ball is calculated as follows;

h = h₀ + vt - ¹/₂gt²

h = 8 + 48t - ¹/₂(32)t²

h = 8 + 48t - 16t²

<h3>Time for the ball to hit the ground</h3>

0 = 8 + 48t - 16t²

solve the above quadratic equation with formula method;

a = -16, b = 48, c = 8

t = 3.15 s

<h3>Time for the ball to be 56 ft above the ground</h3>
  • let upward motion be positive

h = 8 + 48t + 16t²

56 = 8 + 48t + 16t²

0 = -48 + 48t + 16t²

solve the above quadratic equation with formula method;

a = 16, b = 48, c = -48

t = 0.79 s

Learn more about equation of motion here: brainly.com/question/25951773

#SPJ1

5 0
3 years ago
In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro
VladimirAG [237]

Answer:

Margin of error  for a 95% of confidence intervals is 0.261

Step-by-step explanation:

<u>Step1:-</u>

 Sample n = 81 business students over a one-week period.

 Given the population standard deviation is 1.2 hours

 Confidence level of significance = 0.95

 Zₐ = 1.96

Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }

Given n=81 , σ =1.2 and  Zₐ = 1.96

<u>Step2:-</u>

<u />Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }<u />

<u />Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }<u />

On calculating , we get

Margin of error = 0.261

<u>Conclusion:-</u>

Margin of error  for a 95% of confidence intervals is 0.261

<u />

4 0
4 years ago
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