What is the first derivative of this function?

Mathematics

1 answer:

Dvinal [7]2 years ago

7 0

$\bf \cfrac{-9x^2}{8x^5+3}\implies \stackrel{\textit{using the quotient rule}}{\cfrac{(-18x)(8x^5+3)~~-~~(-9x^2)(40x^4)}{(8x^5+3)^2}} \\\\\\ \cfrac{(-144x^6-54x)~~-~~(-360x^6)}{(8x^5+3)^2}\implies \cfrac{-144x^6-54x~~+~~360x^6}{(8x^5+3)^2} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \cfrac{216x^6-54x}{64x^{10}+48x^5+9}~\hfill$

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Equation
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$y - 9 = - \dfrac{1}{2} (x + 2)$

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Rearrange the equation
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$y - 9 = - \dfrac{1}{2} (x + 2) \\ \\
 y - 9 = - \dfrac{1}{2}x - 1 \\ \\
 y - 9 + 9 = - \dfrac{1}{2}x - 1 + 9 \ \Longleftarrow \text{add 9 to both side} \\ \\
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slope of the perpendicular line
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slope = 2

(*the slope of the perpendicular line is the <span>negative reciprocal of the slope of line)</span>

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Substitute slope into equation y = mx + c
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y = 2x + c

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Find y-intercept
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y = 2x + c
At point (0, 4)
4 = 2(0) + c
c = 4

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Substitute y-intercept into the equation y = 2x + c
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y = 2x + 4

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Answer: y = 2x + 4
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