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oksano4ka [1.4K]
2 years ago
7

What is the first derivative of this function?

Mathematics
1 answer:
Dvinal [7]2 years ago
7 0

\bf \cfrac{-9x^2}{8x^5+3}\implies \stackrel{\textit{using the quotient rule}}{\cfrac{(-18x)(8x^5+3)~~-~~(-9x^2)(40x^4)}{(8x^5+3)^2}} \\\\\\ \cfrac{(-144x^6-54x)~~-~~(-360x^6)}{(8x^5+3)^2}\implies \cfrac{-144x^6-54x~~+~~360x^6}{(8x^5+3)^2} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \cfrac{216x^6-54x}{64x^{10}+48x^5+9}~\hfill

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vazorg [7]
A, and B look the same so you can choose, but the answer is <span>256<span>x4</span></span>
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Which of these choices show a pair of equivalent expressions? Check all that<br> apply.
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Can someone please help me with this problem asap? Thanks!! :))
ivolga24 [154]

Answer: \$4.34

Step-by-step explanation:

We have the following information:

Fredburguer F, milkshake M and an order of fries f costs \$3.72:

F+M+f=\$3.72 (1)

One Fredburguer is equal to a milkshake plus orders of fries:

F=M+2f (2)

Three milshakes is equal to a Fredburguer plus an order of fries:

3M=F+f (3)

And we are asked: If we have a Fredburguer, a milkshake and two orders of fries, how much do we have to pay?

F+M+2f=x (4)

Well with the first three equations we have a system of equations to solve. Let's begin by isolating F from (3):

F=3M-f (5)

Making (2)=(5):

M+2f=3M-f (6)

Isolating f:

f=\frac{2}{3}M (7)

Substituting (7) in (2):

F=M+2(\frac{2}{3}M) (8)

Isolating F:

F=\frac{7}{3}M (9)

Substituting (7) and (9) in (1):

\frac{7}{3}M+M+\frac{2}{3}M=\$3.72 (10)

Isolating M:

M=\$0.93 (11) This is the cost of a Milkshake

Substituting (11) in (7):

f=\frac{2}{3}\$0.93 (12)

f=\$0.62 (13) This is the cost of an order of frieds

Substituting (11) in (9):

F=\frac{7}{3}\$0.93 (14)

F=\$2.17 (15) This is the cost of a Fredburguer

Substituting (11), (13) and  (15) in (4):

\$2.17+\$0.93+2(\$0.62)=x (16)

Finally:

x=\$4.34 This is the cost of a Fredburguer, a milkshake and two orders of fries

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Answer:

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Step-by-step explanation:

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