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3 years ago

Solve the inequality graphically. 4^x > 2^x

Mathematics

2 answers:

UkoKoshka [18]3 years ago

6 0

Answer:

A. x > 0

Step-by-step explanation:

As long as the number (x) is a number greater than 0, the inequality would be correct. Take for example, 1 (a number greater than 0)

4^1 = 4; 2^1 = 2; 4 > 2

Another example is 2

4^2 = 16; 2^2 = 4; 16 > 4

etc.

Thepotemich [5.8K]3 years ago

4 0

Answer:

A. x > 0

Step-by-step explanation:

see graph

4^x > 2^x

Replace 4 with 2^2

2^2^x > 2^x

a^b^x = a^(b*c) so

2^ 2x > 2^x

If the bases are the same, the exponents must keep the same ratio

2x>x

This is true if x>0

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two numbered 1 to 6 dice are thrown together and their scores are added. the probability that the sum will be 4 is?

natulia [17]

Answer:

$Pr = \frac{3}{36}$

Step-by-step explanation:

Given

2 number die

Required

P(Sum = 4)

The sample space of 2 die is:

$S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6), (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)$

$(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6), (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)$

$(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6), (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)$

$n(S)= 36$

The pairs that adds up to 4 are:

$Sum(4) = \{(1,3), (2,2),(3,1)\}$

$n(Sum) =3$

So, the probability is:

$Pr = \frac{n(Sum)}{n(S)}$

$Pr = \frac{3}{36}$

5 0

3 years ago

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dusya [7]

Answer:

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Step-by-step explanation:

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3 0

4 years ago

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LekaFEV [45]

Answer:

AD=2

Step-by-step explanation:

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4 years ago

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Rus_ich [418]

Answer:

Answer is 49

Step-by-step explanation:

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Answer:

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