Answer:
it is 2/1
Step-by-step explanation:
Answer:
No.
Step-by-step explanation:
It has different order of matrices .
For <em>A</em><em>d</em><em>d</em><em>i</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>or <em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>, both matrices must have the same number of <u>r</u><u>o</u><u>w</u><u>s</u> and <u>c</u><u>o</u><u>l</u><u>u</u><u>m</u><u>n</u><u>s</u> .
Answer:
B. 2/3
Step-by-step explanation:
To solve this we have to take into account this axioms:
- The total probability is always equal to 1.
- The probability of a randomly selected point being inside the circle is equal to one minus the probability of being outside the circle.
Then, if the probabilities are proportional to the area, we have 1/3 probability of selecting a point inside a circle and (1-1/3)=2/3 probability of selecting a point that is outside the circle.
Then, the probabilty that a random selected point inside the square (the total probability space) and outside the circle is 2/3.
