Question

Which is the solution to the following equation? 4x^2-12x+9=5

Answer 1

We assume that
if xy=0
x and y=0

first make it equal to zero

minus 5 on both sides
4x^2-12x+4=0
undistribute 4 for ease
4(x^2-3x+1)=0
since 4 does not equal zero, and the only thing that will get it to zero is 0,
x^2-3x+1=0
use quadratic equation

if you hahve
ax^2+bx+c=0
x=$\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$
1x^2-3x+1=0
a=1
b=-3
c=1

x=$\frac{-(-3)+/- \sqrt{(-3)^{2}-4(1)(1)} }{2(1)}$
x=$\frac{3+/- \sqrt{9-4} }{2}$
x=$\frac{3+/- \sqrt{5} }{2}$
x=$\frac{3+ \sqrt{5} }{2}$ or $\frac{3- \sqrt{5} }{2}$


aprox
x=2.61803 or 0.381966