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BARSIC [14]
3 years ago
5

Factor (if the expression is not factorable using integers, enter prime). 5x^2+4+x

Mathematics
1 answer:
givi [52]3 years ago
4 0

Answer:

This expression does not factor. Neither can I solve it, because I can't plug in the values for x.

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2 years ago
Please tell me what is (7+3x)4
Savatey [412]

Answer:

28+12x

Step-by-step explanation:

Multiply 7 with 4

Multiply 3x with 4

5 0
2 years ago
Read 2 more answers
Show that (x+1) is a factor of f(x)=19x^42+18x-1
Dmitry_Shevchenko [17]

Answer:

see explanation

Step-by-step explanation:

If (x + 1) is a factor then f(- 1) = 0

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Thus (x + 1) is a factor of f(x)

6 0
2 years ago
How would i solve for x and y in 3x+2y=17 and 2x-y=2 by using substitution
maxonik [38]
I’ll do an example problem, and I challenge you to do this on your own!
4x+6y=23
7y-8x=5
Solving for y in 4x+6y=23, we can separate the y by subtracting both sides by 4x (addition property of equality), resulting in 6y=23-4x. To make the y separate from everything else, we divide by 6, resulting in (23-4x)/6=y. To solve for x, we can do something similar - subtract 6y from both sides to get 23-6y=4x. Next, divide both sides by 4 to get (23-6y)/4=x.

Since we know that (23-4x)/6=y, we can plug that into 7y-8x=5, resulting in
7*(23-4x)/6-8x=5
= (161-28x)/6-8x
Multiplying both sides by 6, we get 161-28x-48x=30
= 161-76x
Subtracting 161 from both sides, we get -131=-76x. Next, we can divide both sides by -76 to separate the x and get x=131/76. Plugging that into 4x+6y=23, we get 4(131/76)+6y=23. Subtracting 4(131/76) from both sides, we get
6y=23-524/76. Lastly, we can divide both sides by 6 to get y=(23-524/76)/6

Good luck, and feel free to ask any questions!
4 0
3 years ago
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