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evablogger [386]

3 years ago

7

Write 3 1/3 as an improper fraction I NEED HELP!

2 answers:

weqwewe [10]3 years ago

6 0

Because 1 is equal to 3/3, 3 can be displayed as 9/3. The extra 1/3 would make it 10/3.

lara31 [8.8K]3 years ago

4 0

3 1/3 as an improper fraction would be 10/3! :)

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Explain why y^2 = x (X input, y output) is not a function.

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How do you find the total sum of squared values?

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Step-by-step explanation:

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3 years ago

Write out the sample space for the given experiment. Use the following letters to indicate each choice: M for mushrooms, O for o

pshichka [43]

Answer: {(MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)}

Step-by-step explanation:

Sample space is a set that contains all the possible outcomes for an event.

For salad:

Choices for extra toppings (mushrooms, olives) =2

Choices for meats (bacon, eggs) =2

Choices for dressings (vinaigrette, honey mustard.)= 2

By Fundamental counting principal .

The number of different salads can be made= (Choices for extra toppings) x (Choices for meats ) x (Choices for dressings)

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All the possible outcomes = (MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)

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3 years ago

For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10

professor190 [17]

The true statements are:

Tyson's expression is not equivalent to the original expression
The equivalent expression is: $\frac{1}{2}g- \frac 1{5}$

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}$

Collect like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10} -\frac{1}{10}$

Evaluate the like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}$

Tyler's equivalent expression is given as:

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}$

Collect like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}$

Evaluate the like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g$

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

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2 years ago