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Nataliya [291]
3 years ago
8

Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, or n

o solution. Explain your
answers.
(a) 2x+4(x-1)=2+4x
(b) 25-x=15-(3x+10)
(c) 4x=2x+2x+5(x-x)
Mathematics
1 answer:
OLga [1]3 years ago
7 0
I think its 4x=2x+2x+5(x-x)
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Step-by-step explanation:

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Step-by-step explanation:

it is the square + the circle

15*25+πr²

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Read 2 more answers
A company makes three sizes of juice bottles: small, medium, and large.
Ivahew [28]

An expression in terms of s that represents the number of large bottles is :  L = (\frac{15s}{2} /3})

<h3>Ratio of different sizes of bottles </h3>

The company makes s small bottles every minute

let ; M represent the number of medium bottles made every minute

L represent the number of large bottles made every minute

small bottles to medium =  2 : 3

small bottles to medium =  s : M

M is the unknown, so to find how many medium bottles that has been made,  we must cross multiply

2M = 3s

M = \frac{3s}{2}  medium bottles made every minute

medium bottles to large bottles =  3 : 5

medium bottles to large bottles =  M : L

where M = \frac{3s}{2}

The equation becomes:

           3 : 5

           \frac{3s}{2} : L

L is the unknown, so to find how many Large bottles that has been made,  we must cross multiply

3L =( \frac{3s}{2} ) * 5

L = (\frac{15s}{2} /3})

L = ( \frac{5}{2} s)

L = 2.5 s

therefore the large bottles the company makes every minute is 2.5s large bottles

we can conclude that the expression for the number of large bottles the company makes every minute with respect to s is : L = 2.5 s

Learn more about Ratio : brainly.com/question/1509142

8 0
1 year ago
Find each unit price to decide which is the better buy. Your answer: 0 3 sodas por $2.70 o 10 sodas por $9.10 6 sodas for $5.58​
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Answer hi

Step-by-step explanation:

hi

3 0
2 years ago
Inequality n &lt; -5<br> HELPPP ASAPPP
ale4655 [162]

Answer:

please give me a brainless 0

Inequality :

α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x

The following is as far as I get:

α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x

(n−1)a−(⌊n÷m⌋×(a−b))≥x−α1

n−1−(⌊n÷m⌋×(a−b))≥x−α1a

n−(⌊n÷m⌋×(a−b))≥x−α1a + 1

Step-by-step explanation:

3 0
3 years ago
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