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2 years ago

9

Please help i don't know this (6th grade math)

1 answer:

andrew-mc [135]2 years ago

5 0

Answer:

y=7

Step-by-step explanation:

62y=434

Divide both sides my 62

y=434/62

y=7

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In the Itty Bitty High School, there are 85 students. There are 27 students who take French, 51 who take Geometry and 38 who tak

andrew-mc [135]

Answer:

58 students

Step-by-step explanation:

Given

$Total = 85$

$French = 27$

$Geometry = 51$

$History = 38$

$None = 5$

$All = 2$

Required

Students that take only 1 subjects

The attached image illustrates the question.

For French only (x), we have:

$x + 7 -2+10-2+2=27$

$x + 15=27$

Collect like terms

$x =- 15+27$

$x =12$

For Geometry only (y), we have:

$y+10-2+15-2+2=51$

$y+23=51$

Collect like terms

$y=-23+51$

$y=28$

For History only (z), we have:

$z +15-2+7-2+2=38$

$z +20=38$

Collect like terms

$z =-20+38$

$z =18$

Students with one subject is then calculated as:

$1\ subject = x+y+z$

$1\ subject = 12 + 28 + 18$

$1\ subject = 58$

5 0

3 years ago

Solve for z: -14z - -16z - -8z - 11z +7z = -12

Jet001 [13]

-2. gv. gv. vv. g v gvv

8 0

3 years ago

8. Solve the following triangle for all missing sides and angles.

vova2212 [387]

Answer:

Parte1 :

∡B= 180 - (42 + 83)= 55°

Parte2 :

Using the law of sines : $\frac{sin 42}{a} = \frac{sin 55}{175}$ ⇔ $a = sin42 \frac{175}{sin 55}$ ⇔ a= 142.95

Parte3 :

Using the same law : $c = sin 83\frac{a}{sin 42}$ or $c= sin 83\frac{175}{sin 55}$ ⇔ c= 212.04

7 0

3 years ago

5 2x=2x 6 how do you solve this problem

Maslowich

If it is 5+2x=2x+6 than the answer is no solution

7 0

2 years ago

Which expressions show a way to solve this problem? marsha had 54 beads. she kept 14 of the beads and shared the rest equally am

leonid [27]

54 - 14 = 40
40/5 = 8
Each friend recieved 8 beads

8 0

3 years ago