2 years ago

(Had to re-upload - Chose the wrong picture and couldn't edit.

1 answer:

5 0

7.1

Use pythogoras theorem to obtain the answer.

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9966 [12]

Answer:

D) b = $\frac{S-2ac}{2a + 2c}$

Step-by-step explanation:

First, move all the terms that do not include b to the left side with S:

S = 2ab + 2bc + 2ac

S - 2ac = 2ab + 2bc

Now, factor out 2b from the right side:

S - 2ac = 2b(a + c)

Divide both sides by 2(a + c):

b = $\frac{S-2ac}{2(a + c)}$

Finally, multiply out the denominator:

b = $\frac{S-2ac}{2a + 2c}$

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igomit [66]

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The sum(9) of half of the first number(1/2a) and one third of the second number(+1/3b)
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2 years ago

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Elis [28]

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