Answer:
65.3%.
Step-by-step explanation:
The general formula is:
nCr p^r (1 - p)^(n-r) where n = number of trials, p =probability of success on one trial , r = the given number of successes
So for 2, 3 or 4 success ;
probability = 5C2 (0.4)^2 (0.60)^(5-2) + 5C3 (0.4)^3 (0.60)^(5-3)
+ 5C4 (0.4)^4 (0.60)^(5-4)
= 0.3456 + 0.2304 + 0.0768
= 0.6528.
Answer:
OK I am 85% sure on this for the 13 year old its ( 23 to 112 )
and for the older kids ( 147 to 48 ) or (23:112) (147:48)
hope it helps if it doesn't sorry.
Step-by-step explanation:
Answer:
CP of 1bulb =Rs10
CP of 250bulbs=Rs2500
Number of defective bulbs 12
remaining bulbs =250−12=238
SP of 1bulb =Rs12
SP of 238bulbs=Rs2856
profit=Total SP-CP=2856−2500=Rs356
profit%=[
CP
loss
×100]=
2500
356
×100=14.24%
Step-by-step explanation:
Answer:
m
Step-by-step explanation:
m
Answer:
e
Step-by-step explanation:
