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umka21 [38]
3 years ago
5

The pie chart to the right shows how adults rate their financial shape. Suppose 4 people are chosen at random from a group of 11

00. what is the probability that all four would rate their financial shape as excellent? (make the assumption that the 1100 people are represented by the pie chart)
PIE CHART DATA:
Excellent 7%
Good 44%
Fair 35%
Poor 13%
Other 1%
Mathematics
2 answers:
vekshin13 years ago
8 0

Answer:

Step-by-step explanation:

Given that a pie chart shows data as

Excellent 7%

Good 44%

Fair 35%

Poor 13%

Other 1%

If 4 people are chosen at random we find that each person is independent of other and there are two outcomes either excellent or not excellent.

p = Prob for success = p = 7%=0.07

q = Prob for non success = 1-0.07 = 0.93

If x is a random variable representing the excellent persons then X is binomial with n =4, p = 0.07

Required probability = P(X=4)

=p^4\\=(0.07)^4\\=0.00002401

Over [174]3 years ago
3 0

Answer:

0.000022304

Step-by-step explanation:

Total number of people = 1100

Number of people chosen = 4

Excellent percentage is 7% or 0.07

So, number of people rated excellent = 0.07\times1100= 77

Others who did not choose excellent = 1100-77=1023

So, p(randomly choose 4 excellent)= \frac{(77C4)(1023C0)}{1100C4}

= \frac{77C4}{1100C4}

=1353275/60671970975 = 2.2304e^{-5}

= 0.000022304

Or second and easy method is simply multiplying:

\frac{77}{1100} \times\frac{76}{1099} \times\frac{75}{1098} \times\frac{74}{1097}

= 32478600/1456127303400 = 0.000022304

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For the given set, first calculate the number of subsets for the set, then calculate the
vodomira [7]

Answer:

\fbox{\begin{minipage}{14em}Number of subsets: 16\\Number of proper subsets: 15\end{minipage}}

Step-by-step explanation:

<em>Given:</em>

The set A = {5, 13, 17, 20}

<em>Question: </em>

Find the number of subsets of A

Find the number of proper subsets of A

<em>Simple solution by counting:</em>

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{∅} - 1 set

Subset of A that has 1 element:

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<u><em>Key-point:</em></u>

The counting method might be used for finding the number of subsets when the original set contains few elements.

The question is that, for a set that contains many elements, how to find out the number of subsets?

The answer is that: there is a fix formula to calculate the total number (N) of subsets of a set containing n elements: N = 2^{n}

With original set A = {5, 13, 17, 20}, there are 4 elements belonged to A.

=> Number of subsets of A: N = 2^{4} = 16

(same result as using counting method)

<em>Brief proof of formula: N = </em>2^{n}<em />

Each element of original set is considered in 2 status: existed or not.

If existed => fill that element in.

If not => leave empty.

For i.e.: empty subset means  that all elements are selected as not existed, subset with 1 element means that all elements are selected as not existed, except 1 element, ... and so on.

=> From the point of view of a permutation problem, for each element in original set, there are 2 ways to select: existed or not. There are n elements in total. => There are 2^n} ways to select, or in other words, there are 2^{n} subsets.

Hope this helps!

:)

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