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ioda
3 years ago
10

what is the equation, in slope- intercept form, of the line that contains the points (-3,4) and (5,7)

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

y = \frac{3}{8} x + \frac{41}{8}

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

To calculate the slope use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 4) and (x₂, y₂ ) = (5, 7)

m = \frac{7-4}{5+3} = \frac{3}{8}, hence

y = \frac{3}{8} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

using (5, 7 ), then

7 = \frac{15}{8} + c ⇒ c = 7 - \frac{15}{8} = \frac{41}{8}

y = \frac{3}{8} x + \frac{41}{8} ← equation in slope-intercept form


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