Consider A to be at (0,0)
B lies on the circle with center at (0,0) and radius 190
The ship ended up at a point P on a circle with center at (0,0) and radius 270, such that BP = 180
If we let B be due north of A, then the bearing of P from B is z degrees, where
cosz = 80/180
Now you can find the angle θ that the ship is off via
tanθ = 180sinz/270 = 2/3 sinz
Answer:
It is same.
The PS and RS leg which has the same length allow the use of HL by providing the same degree of angle.
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(9,3) I believe. Because to get from -3 to -9 you multiply by three, as well as 5 to 15. So you simply multiply multiply these coordinates by three.
Slope = (y2-y1)/(x2 - x1)
Slope = (6 - 4)/(-4 - 0)
Slope = 2/-4
Slope = - 1/2
2(1)/((1)^2-3)^3
=2/(1-3)^3
=2/(-2)^3
=2/-8
=-1/4