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bija089 [108]
4 years ago
10

What is the equation of the given line in the point-slope form

Mathematics
1 answer:
Genrish500 [490]4 years ago
4 0
First using the given two points we can find the slope (m) of the line

Slope = m =  \frac{Rise}{Run} \\  \\ 
m= \frac{4-1}{3-0} \\  \\ 
m=1

Thus the slope of given line is 1.

Using slope and a point (0,1) we can write the equation in point slope form as

y - 1= 1(x-0)
y - 1 = x

The above equation is the point-slope form of the equation.
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Consider a function that describes how a particular cars gas mileage depends on its speed. What would be an appropriate domain f
Elina [12.6K]

gas mileage = k*s, where k is a constant of proportionality and s is the speed. Unfortunately, this does not take into account the fact that the engine consumes fuel even when the car is not moving.


Here it makes most sense to regard {0, S} as the domain for this function. Here, S would represent the car's top speed.


8 0
3 years ago
Read 2 more answers
How do I solve #7? do i add all the angles together like a normal triangle and make it equal to 180?
kobusy [5.1K]

Answer:

126 degrees

Step-by-step explanation:

Triangle: y = 180 - (5x + 4x)

Straight angle: y = 180 - (4x + 30)

180 - (5x + 4x) = 180 - (4x + 30)

5x + 4x = 4x + 30

5x = 30

x = 6

Angle:

y = 180 - (5x + 4x)

y = 180 - 9x

y = 180 - 9(6)

y =  126

7 0
2 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
Please help me if you don't mind work out the problem I'll give you brainly
svp [43]

Answer:

C) Izzy

Step-by-step explanation:

Justin typed 90 words in 2 minute:

work

405/9=45 words a minute

45*2=90

Remmy typed 84 words in 2 minute:

work

420/10=42 words a minute

42*2=84

Izzy typed 98 words in 2 minutes:

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588/12= 49 words a minute

49*2 = 98

I hope this helps :)

6 0
3 years ago
Read 2 more answers
Urgent!!! Will give thanks and branliest!
agasfer [191]
Okay so, togo flies 30 miles in 3/5 of an hour with the wind.togo flies 30 miles in 5/6 of an hour against the wind. his rate of speed with the wind was 30 / (3/5) = 30*5/3 = 150/3 = 50 mph.his rate of speed against the wind was 30 / (5/6) = 30*6/5 = 6*6 = 36 mph.3/5 of an hour times 50 mph = 30 miles.
5/6 of an hour times 36 mph = 30 miles.mph looks good.
going he was with the wind.
his rate of speed then was the airplane speed plus the wind speed.coming back he was against the wind.his rate of speed then was the airplane speed minus the wind speed.-----50 mph = A + W36 mph = A - W-----looks like A + W - (A - W) should equal 50 - 36.removing parentheses, equation becomesA + W - A + W = 14.
combining like terms, the equation becomes2*W = 14.dividing both sides by 2, equation becomesW = 7.if W = 7, then A can be found as follows:50 = A + 7A = 43.likewise,36 = A - 7A = 43.since the airplane speed is the same, it looks like the answer is good.solving in the original equations, we get3/5 * (43 + 7) = 303/5 * 50- = 3030 = 30good.-----5/6 * (43 - 7) = 305/6 * 36 = 3030 = 30good.
answer is W = 7 and A = 43.
8 0
3 years ago
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