Answer:
28 feet farther than 1st ball.
Step-by-step explanation:
We have been given that Susan threw a softball 42 yards on her first try and 
yard on her second try.
To find second ball is how much farther from the 1st ball, we will subtract 42 yards from yards.
Let us have a common denominator.
Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.
Step-by-step explanation:
could you please mark me as the brainliest answer
Answer:
26.13 sale price discount 12.87
Step-by-step explanation:
I do not know how to explain it to where you will understand it but the sale price is 26.13 and the discount it 12.87
Hope that helps
We can find this using the formula: L= ∫√1+ (y')² dx
First we want to solve for y by taking the 1/2 power of both sides:
y=(4(x+1)³)^1/2
y=2(x+1)^3/2
Now, we can take the derivative using the chain rule:
y'=3(x+1)^1/2
We can then square this, so it can be plugged directly into the formula:
(y')²=(3√x+1)²
<span>(y')²=9(x+1)
</span>(y')²=9x+9
We can then plug this into the formula:
L= ∫√1+9x+9 dx *I can't type in the bounds directly on the integral, but the upper bound is 1 and the lower bound is 0
L= ∫(9x+10)^1/2 dx *use u-substitution to solve
L= ∫u^1/2 (du/9)
L= 1/9 ∫u^1/2 du
L= 1/9[(2/3)u^3/2]
L= 2/27 [(9x+10)^3/2] *upper bound is 1 and lower bound is 0
L= 2/27 [19^3/2-10^3/2]
L= 2/27 [√6859 - √1000]
L=3.792318765
The length of the curve is 2/27 [√6859 - √1000] or <span>3.792318765 </span>units.
