All categories

3 years ago

Calculate the fraction: 3/2x 15/4 Plssss help solve...

1 answer:

5 0

Idk if you’re using that x as times or just a x
If u are using it as times the answer is 45/8
Or 5 5/8
Use photomath and sub to pewdiepie

You might be interested in

15m is what percent of 1.5km?

Papessa [141]

1.5km = 1500m
To find the percentage take 15 and divide it by 1500, then times by 100
15/1500 x 100 = 1%

3 0

3 years ago

Nine out of ten students prefer math class over lunch. How many students do not prefer math if 200 students were asked?

fredd [130]

So, 9 out of 10 students prefer class, so, obviously, it would not be 100. It would be 150. So in conclusion, 50 students prefer lunch over math class, whilst 150 other students prefer math class over lunch.

3 0

3 years ago

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacemen

mamaluj [8]

<h2>Answer:</h2>

(a)

The probability is : 1/2

(b)

The probability is : 1/2

<h2>Step-by-step explanation:</h2>

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2) (1,3) (1,4) (1,5)

(2,1) (2,3) (2,4) (2,5)

(3,1) (3,2) (3,4) (3,5)

(4,1) (4,2) (4,3) (4,5)

(5,1) (5,2) (5,3) (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

We know that it could be calculated by using the formula:

$P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}$

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is: (4,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( since, the only outcome out of 20 outcomes is: (3,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

7 0

3 years ago

20 points! Please help! Which graph represents the function?

Arte-miy333 [17]

I’m pretty sure they both are functions

6 0

3 years ago

PLZZZ HELP THIS IS A BIG PART OF MY GRADE!!!!!! PLZ DON'T JUST TAKE POINTS PLZZZZ. I ONLY NEED B!!

Ulleksa [173]

Answer: I need more evindence to answered it but I say its the third one

Step-by-step explanation:

4 0

3 years ago