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3 years ago

13

-|2x+3|>2 algebraic expression graph and interval notation

1 answer:

Nadusha1986 [10]3 years ago

4 0

-|2x+3| > 2 and <span>-|2x+3| > - 2

</span>-2x+3 > 2
-2x > 2 - 3
-2x > -1
-2x / -2 > -1 / -2
x < 1/ 2

-|2x+3| > - 2
x < 5/2

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Answer:

151.77

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Step-by-step explanation:

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2 years ago

a tabletop in the shape of a trapezoid has area an of 6,550 square centimeters. Its longer base measures 115 centimeters, and th

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To find the missing dimension of the tabletop, the height, you will use the formula for finding the area of a trapezoid and solve for the missing height.

A = 1/2 h (b1 + b2)
6550 = 1/2 h (115 + 85)
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3 years ago

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2 years ago

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The Great Pyramid in Giza, Egypt, is a square pyramid. The dimensions of the pyramid at the time of its completion are shown in

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Answer:

Area of square pyramid is $153883.8\ m^{2}$ .

Step-by-step explanation:

Diagram of the given scenario is shown below,

Given that,

The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is $154 \ m^{2}$ . The side of the square is $230 \ m$ and The height of each triangle is $187 \ m$ .

So, Area of Square shape = $154 \ m^{2}$

Side of square = $230 \ m$

Height of each triangle = $187 \ m$

Finding the Height of triangular shape which is here known as slant height.

In Δ ABO, applying Right angle pythagorean Theorem,

Base $(BO)$ = $\frac{230}{2} = 115\ m$

Height $(AO)$ = $187\ m$

Now,

∴ $AB^{2} = AO^{2} \ + \ BO^{2}$

⇒ $AB= \sqrt{AO^{2} \ + \ BO^{2} }$

⇒ $AB= \sqrt{187^{2} \ + \ 115^{2} }$

⇒ $AB= \sqrt{34969 \ + \ 13225 }$

⇒ $AB= 219.53 \ m$

Then,

Area of square pyramid = $area \ of \ square + \ 4\times area \ of \ traiangle$

= $side\times side + 4\times\frac{1}{2}\times AB\times Base$

= $230\times 230 \ + 2\times 219.53\times 230$

= $52900 + 100983.8$

= $153883.8 \ m^{2}$

Hence, Area of square pyramid is $153883.8\ m^{2}$ .

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2 years ago