The minimum value for 2x is 0
<span>the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC </span>
<span>base AB = 52 and vertical angle 2x + 34° </span>
<span>For the sine law </span>
<span>(sin 2x)/22 = (sin ADB)/AB </span>
<span>(sin 34°)/30 = (sin BDC)/BC </span>
<span>is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from </span>
<span>(sin ADC)/AB = (sin BDC)/BC </span>
<span>it follows </span>
<span>(sin 2x)/22 = (sin 34°)/30 </span>
<span>sin 2x = 22 (sin 34°)/30 </span>
<span>2x = asin(22 (sin 34°)/30) ≈ 24.2° </span>
<span>x = 0.5 asin(22 (sin 34°)/30) ≈ 12.1° </span>
<span>0 < x < 12.1°</span>
Answer:
Move all terms that don't contain x to the right side and solve.
x = −2
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
=========================
next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
=============
2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
There are two methods to solve this problem. One of them is the typical method and the other one is the short-cut. I will explain the shortcut
Short-cut:
This method is quick and easy, and works with ALL triangles, which is why I suggest you use this. You make proportions. Since the triangles are similar, we can use CPCTC. Thereafter,

Now, you just need to identify the terms, substitute, and solve for the unknown, which would be k.

[/tex]
So we found k, but it is asking for BE. Therefore, plug in the value of k, which is 11, into the expression for BE, which is k-7.
BE=K-7
k=11
BE=11-7
BE=4
Your answer is 4.
1. Move all terms to one side
2x^2+3x+1=0
2. Find the numbers for a, b and c
a=2
b=3
c=1
3. Put the numbers into the formula
3^2-4(2)(1)
4. Simplify
9-4*2*1
9-8
1