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wariber [46]
3 years ago
7

1. Does the data in the table below represent exponential growth or exponential decay?

Mathematics
1 answer:
Temka [501]3 years ago
8 0

Exponential decay because it is decreasing

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I need help with this
djverab [1.8K]
B is the rational number since 0 is a rational number and A can't be the rational number because it goes on forever.
The attachment shows work for A and B

8 0
3 years ago
I will give brainlest and 100 points<br><br><br> 28times 48 - 5 times 34
Maru [420]

Answer:

28 x 48 = 1344 - 5X43=170

1344-170=1174

6 0
4 years ago
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PLEASE HELP I WILL AWARD BRAINLIEST!!
Artyom0805 [142]

Answer:

see below

Step-by-step explanation:

1. m∠DEF = m∠_FEK___ = 44° = Def. of ∠ bisector  

2. m∠DEK = m∠_DEF___+m∠FEK___= _angle addition postulate________________

3. m∠DEK = _44___ + _44___ = 88° = Substitution, Algebra  

4. DE = _KE____ = Given  

5. EF = _FE____ = Reflexive property

6. △DEF ≅ △_KEF____ = _SAS postulate________________

7. DF = FK_____ = ___CPCTC  (corresponding parts of congruent triangles are congurent)______________

8. KF = 1/2DK =8 _____ = Algebra, 7

5 0
3 years ago
Solve the following system of equations by using the inverse of a matrix.
Zepler [3.9K]

Answer:

(x, y, z) = (-8,4,-2)

Step-by-step explanation:

.......................................

6 0
4 years ago
What is the distance between B to A<br> Please add the method.<br> The angle is 61 (a bit blurry)
deff fn [24]

Answer:

24.03 units (nearest hundredth)

Step-by-step explanation:

The distance between B and A is:  AB = AH + HB

We have been given AH, so we just need to find the measure of HB.

First, find the angle AOH using tan trig ratio:

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

  • \theta = ∠AOH
  • O = AH = 8
  • A = OH = 19.80

\implies \sf \tan(\angle AOH)=\dfrac{8}{19.8}

\implies \sf \angle AOH = 22.00069835^{\circ}

   ∠BOA = ∠BOH + ∠AOH

⇒ ∠BOH = ∠BOA - ∠AOH

⇒ ∠BOH = 61° - 22.00069835°

               = 38.99930165°

Now we can find HB by again using the tan trig ratio:

Given:

  • \theta = ∠BOH = 38.99930165°
  • O = HB
  • A = OH = 19.80

Substituting given values:

\implies \sf \tan(38.99930165^{\circ})=\dfrac{HB}{19.80}

\implies \sf HB=19.80 \tan(38.99930165^{\circ})

\implies \sf HB=16.03332427

Therefore:

   AB = AH + BH

⇒ AB = 8 + 16.03332427

         = 24.03 units (nearest hundredth)

3 0
2 years ago
Read 2 more answers
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