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3 years ago

Write the value of each digit for the given number 2904

Mathematics

1 answer:

Rudik [331]3 years ago

8 0

Hello there!

The correct answer is two thousand, nine hundred and four.

Hope This Helps You!
Good Luck :)

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Given the function f(x) = 2|x + 6| -4, for what values of x is f(x) = 6?

photoshop1234 [79]

Answer:

f(x) = 2|x + 6|-4

6=2|x + 6|-4

10= 2|x + 6|

divide by 2

5=|x + 6|

x = 5-6

x = -1

so x should be -1

4 0

3 years ago

This is slopes is this supposed to be negative or positive????

Shtirlitz [24]

This slope will be zero

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3 years ago

The explicit rule for a sequence is given.

tamaranim1 [39]

$a_{1}=3$

$a_{n}=16a_{n-1}$

just use the standart recursive for geometric sequence

6 0

3 years ago

Read 2 more answers

kala is saving money to buy a bike that cost $125. She has $60 and will save an additional $5 each week. In how many weeks will

Kaylis [27]

In exponential form it’s: 125=60(1.05)^x
So it should be around 15.043 weeks
If you have to round up to then next week then the answer is 16 weeks she will have enough money to buy the bike. I’m

5 0

2 years ago

Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12

tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})$

$\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12$

5 0

2 years ago