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3 years ago

Can someone help me solve this equation for 3/4w-1/2w-4= 12

Mathematics

1 answer:

muminat3 years ago

3 0

Multiply both sides by 4
3w-2w-16=48
Combine like terms
w-16=48
Add 16 on both sides
w=64

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3s+2t−3 =c<br> −7s−5t =4<br>

irinina [24]

Answer:

−4

s−t+

−4

Step-by-step explanation:

Let's solve for c.

3s+2t−3c−7s−5t=4

Step 1: Add 4s to both sides.

−3c−4s−3t+4s=4+4s

−3c−3t=4s+4

Step 2: Add 3t to both sides.

−3c−3t+3t=4s+4+3t

−3c=4s+3t+4

Step 3: Divide both sides by -3.

−3c

−3

4s+3t+4

−3

−4

s−t+

−4

3 0

3 years ago

If you substracted 3 frome the exponent in an exponential function , what will happen to the graph

Mekhanik [1.2K]

Subtracting a value from the exponent shifts the graph to the right.

So if you subtract 3, the graph would shift 3 units to the right.

6 0

3 years ago

Use differentials to estimate the amount of paint needed (in m3) to apply a coat of paint 0.04 cm thick to a hemispherical dome

pogonyaev

The amount of paint is the volume of paint needed.

The amount of paint needed is 0.065312 cubic meters

<h3>How to determine the amount of paint needed</h3>

The volume of a hemisphere is:

$V = \frac 23\pi r^3$

Differentiate the above equation

$V' = 2\pi r^2 r'$

The above equation represents the estimate of the amount of paint needed.

Where:

r represents the radius (r = 52/2 m)
r' represents the thickness (r' = 0.04 cm)

So, we have:

$V' = 2\pi r^2 r'$

$V' = 2 * 3.14 * (52/2\ m)^2 * (0.04cm)$

$V' = 2 * 3.14 * (26\ m)^2 * (0.04cm)$

Express cm as m

$V' = 2 * 3.14 * (26\ m)^2 * (0.0004m)$

$V' = 0.065312 m^3$

Hence, the amount of paint needed is 0.065312 cubic meters