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777dan777 [17]
3 years ago
5

Eli writes this equation 3/6 + 4/5 = 7/11. Which inequality proves that Eli’s result is incorrect

Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0
He added the numerator and the denominator together.

The correct answer should been 1 3/10 or (1.3)
Minchanka [31]3 years ago
3 0

Answer:

I agree with the dude above he is correct

Step-by-step explanation:

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Please help me I will give brainliest
Pani-rosa [81]

Answer:Yes, I checked.. it is option 2

Step-by-step explanation:

6 0
3 years ago
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Emma was given a system of equations to solve by graphing. Which statement correctly identifies Emma’s error?
Alexxandr [17]

Answer:

line one should have a y-intercept at (0,2).

Step-by-step explanation:

8 0
3 years ago
Please help , I really need it thanks!
Nana76 [90]
The symbol "<=" without quotes means "less than or equal to"

-6x + 2y <= 42
-6x + 2y + 6x <= 42 + 6x ... Add 6x to both sides
2y <= 6x + 42
2y/2 <= 6x/2 + 42/2 ... divide every term by 2
y <= 3x + 21

So the answer is choice D
4 0
4 years ago
Find the measure of angle eight in each triangle round each answer to the nearest 10th
vlada-n [284]

Answer:

# m∠A = 65.3°

# m∠A = 25.8°

# m∠A = 22.7°

Step-by-step explanation:

* Lets revise the trigonometry function to solve the problem

- In any right angle triangle:

# The side opposite to the right angle is called the hypotenuse

# The other two sides are called the legs of the right angle

* If the name of the triangle is ABC, where B is the right angle

∴ The hypotenuse is AC

∴ AB and BC are the legs of the right angle

- ∠A and ∠C are two acute angles

- For angle A

# sin(A) = opposite/hypotenuse

∵ The opposite to ∠A is BC

∵ The hypotenuse is AC

∴ sin(A) = BC/AC

# cos(A) = adjacent/hypotenuse

∵ The adjacent to ∠A is AB

∵ The hypotenuse is AC

∴ cos(A) = AB/AC  

# tan(A) = opposite/adjacent

∵ The opposite to ∠A is BC

∵ The adjacent to ∠A is AB

∴ tan(A) = BC/AB

* Lets solve the problems

# In Δ ABC

∵ m∠B = 90°

∵ AB = 2.3 ⇒ adjacent to angle A

∵ BC = 5 ⇒ apposite to angle A

- To find m∠A use the tangent function because we have opposite

  and adjacent sides

∴ tan A = BC/AB

∴ tan A = 5/2.3 ⇒ use tan^-1 to find m∠A

∴ m∠A = tan^{-1}\frac{5}{2.3}=65.29756

* m∠A = 65.3°

# In Δ ABD

∵ m∠B = 90°

∵ AB = 5.4 ⇒ adjacent to angle A

∵ DA = 6 ⇒ the hypotenuse

- To find m∠A use the cosine function because we have adjacent

  and hypotenuse sides

∴ cos A = AB/DA

∴ cos A = 5.4/6 ⇒ use cos^-1 to find m∠A

∴ m∠A = cos^{-1}\frac{5.4}{6}=25.84193

* m∠A = 25.8°

# In Δ ABE

∵ m∠B = 90°

∵ EB = 2.4 ⇒ opposite to angle A

∵ EA = 6.8 ⇒ the hypotenuse

- To find m∠A use the sine function because we have opposite

  and hypotenuse sides

∴ sin A = EB/EA

∴ sin A = 2.4/6.8 ⇒ use sin^-1 to find m∠A

∴ m∠A = sin^{-1}\frac{2.4}{6.8}=22.6673

* m∠A = 22.7°

3 0
3 years ago
PLEAEE HELP!!!
MrRa [10]
D) Radius
It is going from the center to a point on the circle

7 0
3 years ago
Read 2 more answers
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