Multiply.

1 answer:

3 0

(2/6) × 24 = m
(1/3) × 24 × 3(to take out (1/3)) = m × 3
24 = m×3
24÷3 = m×3 ÷3
8 = m
m = 8

So the answer should be B. 8

Hope I can help :)

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How would you answer the second question?

morpeh [17]

The same column vector but positiv (5/4)

5 0

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2. Let A, B and c be three towers. The bearing of B from A is 120° and angle BC is 68º. The distance from Tower A to Tower B is

g100num [7]

(i) The bearing of B from A and angle x are supplementary, then:

$\begin{gathered} 120\degree+x=180\degree \\ x=180\degree-120\degree \\ x=60\degree \end{gathered}$

(ii)

From the above diagram, the bearing angle of A from B is:

$120\degree+180\degree=300\degree$

(iii)

From the above diagram, the bearing angle of C from B is:

$180\degree+52\degree=232\degree$

(iv)

Applying the law of cosines with the sides AB = 145m and CB = 240 m, and the angle ABC = 68°, the distance AC is:

$\begin{gathered} AC^2=AB^2+CB^2-2\cdot AB\cdot CB\cdot cos\left(\angle ABC\right) \\ AC^2=145^2+240^2-2\cdot145\cdot240\cdot cos(68\degree) \\ AC^2=21025+57600-69600\cdot cos(68\operatorname{\degree}) \\ AC^2=52552.3811 \\ AC=\sqrt{52552.3811} \\ AC\approx229\text{ m} \end{gathered}$