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vagabundo [1.1K]
3 years ago
15

How to solve for the missing sides

Mathematics
1 answer:
yaroslaw [1]3 years ago
5 0
Y equals 2 and x equals 2√2
I gave you an explanation in the other question
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Hello! I need help with this problem thanks!!
Helen [10]

Answer:

10 tomato plants and

15 rose plants

Step-by-step explanation:

Let t be the no. of tomato plants,

And r the no. of rose plants

t + r = 25

t + 2r = 40

t = 25 - r

25 - r + 2r = 40

r = 15

t = 25 - 15

t = 10

8 0
3 years ago
A bubble solution contains 3/4 cup of corn starch for every 2 cups water. What is the rate in cups of corn starch per cup of wat
bezimeni [28]

Answer:

3/8 cup of corn starch per cup of water

Step-by-step explanation:

hope dis help

8 0
2 years ago
Use the Green's Theorem to calculate the work done by the field [ F (x, y) = -3y^5 i + 5y^2x^3 j ] to move a particle along the
lianna [129]
\displaystyle\int_C\mathbf F\cdot\mathrm d\mathbf r=\iint_R\left(\frac{\partial(5y^2x^3)}{\partial x}-\frac{\partial(-3y^5)}{\partial y}\right)\,\mathrm dx\,\mathrm dy

\dfrac{\partial(5y^2x^3)}{\partial x}=15y^2x^2
\dfrac{\partial(-3y^5)}{\partial y}=-15y^2

=\displaystyle\int_{x=-2}^{x=2}\int_{y=-\sqrt{4-x^2}}^{y=\sqrt{4-x^2}}15y^2(x^2+1)\,\mathrm dy\,\mathrm dx

Converting to polar coordinates, the integral is equivalent to

=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}15r^3\sin^2\theta(r^2\cos^2\theta+1)\,\mathrm dr\,\mathrm d\theta
=\displaystyle15\int_0^{2\pi}\int_0^2\left(\frac{r^5}4\sin^22\theta+r^3\sin^2\theta\right)\,\mathrm dr\,\mathrm d\theta
=\displaystyle\frac{15}4\left(\int_0^2r^5\,\mathrm dr\right)\left(\int_0^{2\pi}\sin^22\theta\,\mathrm d\theta\right)+15\left(\int_0^2r^3\,\mathrm dr\right)\left(\int_0^{2\pi}\sin^2\theta\,\mathrm d\theta\right)
=100\pi
6 0
3 years ago
-5x+3=4x-69<br>how do you solve <br>algebra plz help​
Amanda [17]
X=8
i learned this math class
6 0
3 years ago
Read 2 more answers
When a number is written in scientific notion, how can you tell right away whether or not it is or than or equal to one?
nikklg [1K]
Well, to know right away whether or not a number is equal to 1, you need to know what 1 is in scientific notation. 1 * 10^0. Easy enough :) To know if the number is greater than one, any positive number multiplied by 10^a number higher than 0 is greater than one. As well as any number greater than one multiplied by 10^0 or a positive number. For numbers less than one, the way to know is if the number is being multiplied by 10 ^ a negative number. I hope this helps :)
8 0
3 years ago
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