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zimovet [89]
4 years ago
12

Need help with 7 and 8 please

Mathematics
2 answers:
iren2701 [21]4 years ago
3 0

7 is “what was our opinion of the experiment and results?”

8 is “random”

pishuonlain [190]4 years ago
3 0

Number 7 is an opinion of your experiment and your results that you got that’s it and 8 is random I think I hope this helps you

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HELP PLEASE!!!!!!!:(
NemiM [27]

Answer:

D

Step-by-step explanation:

\frac{1}{2} = \frac{7}{14} \\

\frac{1}{7}  = \frac{2}{14}

\frac{7}{14}  + \frac{2}{14}  = \frac{9}{14}

5+2=7

7 + \frac{9}{14}  = 7 \frac{9}{14}

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Use the fraction bar interactive tool to find the lowest common denominator before subtracting 2 3 from 5 6 . What is the lowest
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Step-by-step explanation:

5/6 - 4/6 = 1/6

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Answer:1/20

Step-by-step explanation:

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At a point on the ground 80 ft from the base of a tree, the distance to the top of the tree is 11 ft more than 2 times the heigh
Sergio039 [100]

Let h be the height of the tree and d the distance to the top of the tree from the point on the ground. Draw a diagram to visualize the situation:

Since the distance to the top of the tree is 11 ft more than two times the height, then:

d=2h+11

Use the Pythagorean Theorem to relate the length of the sides of the right triangle:

\begin{gathered} h^2+80^2=d^2 \\ \Rightarrow h^2+6400=(2h+11)^2 \\ \operatorname{\Rightarrow}h^2+6400=(2h)^2+2(11)(2h)+11^2 \\ \operatorname{\Rightarrow}h^2+6400=4h^2+44h+121 \end{gathered}

Notice that we have obtained a quadratic equation in terms of h. Write it in standard form and use the quadratic formula to solve for h:

\begin{gathered} \Rightarrow0=4h^2+44h+121-h^2-6400 \\ \Rightarrow0=4h^2-h^2+44h+121-6400 \\ \Rightarrow0=3h^2+44h-6279 \\ \Rightarrow3h^2+44h-6279=0 \\  \\ \Rightarrow h=\frac{-44\pm\sqrt{(44)^2-4(3)(-6279)}}{2(3)} \\  \\ \therefore h_1=39 \\ h_2=-53.666.. \end{gathered}

Since the height of the tree must be positive, the only solution is h=39ft. To the nearest foot, the height of the tree is 39.

Therefore, the height of the tree is 39 ft.

4 0
1 year ago
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