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4 years ago

6

Two lines intersect at a point, the vertical lines formed are supplementary. What is the measure of each of the angles?

1 answer:

dolphi86 [110]4 years ago

7 0

Well, supplementary angles add up to 180, and the angles split up because of the intersection. So what do we do? 2x=180 What is x?

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Krissi has $14 in the bank and earns $8 a day. John has 35$ and earns $5 a day when will krissi have more money?

SOVA2 [1]

Answer: 8 days

Step-by-step explanation:

K=14+8x

J=35+5x

when K=J they will have the same amount

14+8x=35+5x

8x=21+5x

3x=21

x=7 days until they have the same amount- 8 days until she has more

5 0

3 years ago

A small business earns a profit of $4,500 in

olchik [2.2K]

Answer:

$2750/month

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The equation y=x^3 + 3 is symmetric with respect to which of he following?

lianna [129]

$y = x^{3} +3$

Subtract 3 from both sides,

$y-3=x^{3}$

Let x = X and y - 3 = Y

Then,

$Y = X^{3}$

So, we have shifted the origin to a point (0, 3).

This is an odd function and the graph of an odd function is symmetrical about the origin.

That is, symmetrical about X = 0, Y = 0

Symmetrical about x = 0,, y - 3 = 0

Symmetrical about x = 0, y = 3.

Hence, the graph is symmetrical about the point (0, 3).

3 0

3 years ago

What is 25% of 40? I need the answer quickly!! First gets 5 stars and a thank you!!

eimsori [14]

Answer:

The answer is 10

I hope this helped and please mark me as brainliest!

6 0

3 years ago

Read 2 more answers

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago