What's the area and perimeter of a right triangle with sides 5, 12 and 13( 5 and 12 are the base and height)

Mathematics

2 answers:

umka21 [38]3 years ago

8 0

Area of <span>a right triangle =base*height/2=5*12/2=5*6=30</span>

uysha [10]3 years ago

7 0

Perimeter is 30
Area is also 30.

Add the numbers to get the perimeter and then use 1/2bh to get the area. <span />

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Figures ABCD and PQRS are parallelogram find x and y (lengths are in metres) Part i and ii.

STatiana [176]

Step-by-step explanation:

For 1st question

In a parm ABCD

5x - 4 = 16 ( being opposite sides of parallelogram)

5x = 16 + 4

5x = 20

x = 20 / 5

x = 4

3y + 1 = 22 (being opposite sides of parallelogram)

3y = 22 -1

3y = 21

y = 21 / 3

y = 7

For second question

In parm PQRS

Diagonals bisect each other so

x + 4 = 12

x = 12 - 4

x = 8

x + y = 32

8 + y = 32

y = 32 - 8

y = 24

Hope it will help :)❤

8 0

3 years ago

How would I start to solve number 15? Would I use distributive property?

natita [175]

$-5-x=2x-(4x+6)$

Using the distributive property is the correct first step. $(4x+6)$ is being multiplied by -1, so distributing gives

$-5-x=2x+(-4x-6)$
$-5-x=2x+((-4x)+(-6))$

Now, using the associative property of addition, you get

$-5-x=(2x+(-4x))+(-6)$
$-5-x=(2x-4x)-6$

Simplify the right hand side:

$-5-x=-2x-6$

Add 5 and $2x$ to both sides.

$(2x+5)-5-x=(2x+5)-2x-6$

On the left side, use the associative property. On the right, commutativity and associativity:

$2x+(5-5)-x=5+(2x-2x)-6$

Simplify.

$2x-x=-1$
$x=-1$