Answer:
60 degrees
Step-by-step explanation:
The angles all have to add up to 180, so you can do
The minimum and maximum of the set alone is 25 and 60. The range of that 35. So, the number is not less than or more than 25 or 60.
The set in order:
25, 36, 48, 52, 60
The median is 48, so the number has to be less than 48. Let's see if the number may be less than 36.
36+48
84
42
So, the number is right between 36 and 48.
43.5×2
87
Let's subtract 48 from that
87-48
39
So, the mssing value is 39. Let's check.
25, 36, 39, 48, 52, 60
48+39
87÷2
43.5
So the missing value is 39.
Answer:
Step-by-step explanation:
The average scores s (on a 100 point scale) for the students can be modeled by
s = 75 - 6 In(t + 1), 0 < t < 12
where t is the time in months.
a) Since the students were given an exam and then retested monthly with equivalent exams, then,
For the original exam, t = 0
Therefore,
s = 75 - 6 In(0 + 1) = 75 - 6 In1
s = 75 - 6 × 0 = 75
b) the average score after 4 months, t = 4
Therefore,
s = 75 - 6 In(4 + 1) = 75 - 6 In5
s = 75 - 9.66 = 65.34
c) s = 60
Therefore,
60 = 75 - 6 In(t + 1)
6 In(t + 1) = 75 - 60 = 15
In(t + 1) = 15/6 = 2.5
t + 1 = e^2.5 = 12.18
t = 12.18 - 1 = 11.18
t = 11 approximately
Answer:
disagree
Step-by-step explanation:
The interquartile range is a measure of how spread out values are in a data set.
It doesn't actually consider the values, it is found by finding the range between the Q1 / 25th percentile and the Q3 / 75th percentile --and a "range" is found by finding the difference between these two numbers (by subtracting).
So, the weather could have been something like:
79 79 79 80 81 81 83 85 96 97
79 79 79 80 81 | 81 83 85 96 97
meaning that the interquartile range is 6, but these temperatures are not low
(if you want me to explain how to find the interquartile range more thoroughly, please let me know)
Relative frequency : total number of diamonds / total number of cards drawn = 11/40=0.3
The answer is 30% : C
