Hope this helps. Solution is attached on the image above.
Answer:
0.0549
0.7617
0.2383
Step-by-step explanation:
Given that:
Probability that incoming email is spam ;
P(spam) = 0.38
If three emails are in my inbox, what is the probability that:
A. All three messages are spam.
P(1st message being spam) * p(second message being spam) * p(3rd message being spam)
= (0.38) * (0.38) * (0.38)
= 0.054872
= 0.0549
B. At least one of the three messages are spam.
1 - p(none of the 3 messages are spam)
P(none of the 3 messages are spam)
P(not spam) = 1 - p(spam) = 1 - 0.38 = 0.62
1 - [P(not spam) * p(not spam) * p(not spam)]
1 - (0.62 * 0.62 * 0.62)
= 1 - 0.238328
= 0.761672
= 0.7617
C. None of the three messages are spam.
P(not spam) = 1 - p(spam) = 1 - 0.38 = 0.62
P(not spam) * p(not spam) * p(not spam)
(0.62 * 0.62 * 0.62)
= 0.238328
= 0.2383
Answer:
-2.3 repeating
Step-by-step explanation:
Answer for the equation by elimination
Answer:
exact form: r= 9/4
decimal form: r=2.25
mixed number form: r= 2 1/4
Step-by-step explanation:
