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makvit [3.9K]
3 years ago
9

June’s health insurance policy requires a copayment of $35 for each office visit and a copayment of $25 for each of her prescrip

tion drugs. June had 6 office visits last year and filled 12 prescriptions. What were her total copayments?
Mathematics
1 answer:
Naddik [55]3 years ago
5 0

<u>ANSWER: </u>

Total co-payment made by June is $510.

<u> SOLUTION: </u>

Given, June’s health insurance policy requires a co-payment of $35 for each office visit.

And a co-payment of $25 for each of her prescription drugs.

June had 6 office visits last year and filled 12 prescriptions.  

We need to find the total co-payments of June.

Total co-payment = co-payment for office visits + co-payments for prescription drugs

Now, co-payment for office visits = co-payment for each office visit \times number of office visits

Co-payment for office visits = 35 \times 6  = 210

Therefore, co-payments for office visits are $210

Now, co-payment for prescription drugs = co-payment for each prescription \times number of prescriptions

Co-payment for prescription drugs = 25 \times 12  = 300

Therefore, co-payments for prescription drugs are $300

Now, Total copayment = copayment for office visits + copayments for prescription drugs

= 210 + 300  = 510

Hence total copayments made by June is $510.

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List the single-digit divisors of 2100.<br> I really need help
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<u>Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:</u>

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