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3 years ago

How to simplify (1-p)(1+p+p^2+p^3+p^4+p^5+p^6)?

1 answer:

7 0

Use FOIL
(1-p)(1+p+p^2+p^3+p^4+p^5+p^6)
1+p+p^2+p^3+p^4+p^5+p^6 -1p - p^2 - p^3 - p^4 - p^5 - p^6
1 + p -1p <------------------Answer

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Need help. greatly appreciated

gizmo_the_mogwai [7]

1. It must be divisible by 2 and 3. It IS divisible by 2. it IS divisible by 3. No remainder.
2. Add the digits and see if the sum is divisible by 3. Apply this rule to both numbers. 3 is not a common factor.
3a. 639
3b. 1035
3c. 179

7 0

2 years ago

Emily thinks the perfect tomato sauce has 8 cloves of garlic in every 500{ mL} of sauce. Raphael's tomato sauce has 12 cloves of

igomit [66]

For perfect solution we need to have :- 8 colves in 500ml solution

500 ml has 8 cloves

1 ml has 8 / 500 cloves

100ml has 8 / 500 * 100 = 8/5 = 1.6 cloves

Raphael's mixture

900 ml has 12 cloves

1 ml has 12 / 900 cloves

100 ml has 12 / 900 * 100 = 12 / 9 = 1.33 cloves

so concentration of garlic in 100 ml solution of Raphael's solution is less than Emily's solution so it is not garlicky enough. ( option B)

5 0

3 years ago

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Convert the polar expression of this complex number into its rectangular form:

Sergio [31]

Answer:MARK BRAINLLEST MARK BRAINLLEST

(−5/2, 5/2√3)

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Step-by-step explanation:

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3 years ago

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(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

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3 years ago

If x^3=216, what is the value of x?

sleet_krkn [62]

Answer:

Step-by-step explanation:

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3 years ago

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