SQ = square root 329 = 20 * SQ (273+ t) Do the inverse of everything on the left Divide by 20 Square your answer (329/20) and subtract 273 from it ((329/20)^2)-273 = t the temperature according to my calculations was <span>-2.3975 degrees The nearest degree, if my math is correct was -2 degrees. I'm not sure how to graph the equation, or I can't graph it for you, rather. Try Desmos if you need to graph it.
