Kiero saber la tabla numérica de 14

Something divided by something equals 132

natta225 [31]

11 x 12 =132
i think this is the right answer

8 0

3 years ago

Help!!

Elza [17]

Answer:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

Step-by-step explanation:

Required

Which equals $x = 4$

$(a)\ 2x + 6 = 2$

Collect like terms

$2x = 2 - 6$

$2x = -4$

Divide both sides by 2

$x = -2$

$(b)\ 2x - 9 = -1$

Collect like terms

$2x = -1 + 9$

$2x = 8$

Divide both sides by 2

$x = 4$

$(c)\ -2x + 12 = 4$

Collect like terms

$-2x =- 12 + 4$

$-2x =-8$

Divide both sides by -2

$x = 4$

$(d)\ 2(x + 2) = 10$

Divide both sides by 2

$x + 2 =5$

Collect like terms

$x = 5-2$

$x = 3$

$(e)\ 2(x - 10) = -12$

Divide both sides by 2

$x - 10 = -6$

Collect like terms

$x = 10 - 6$

$x = 4$

Hence, the equations with the required solution are:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

3 0

3 years ago

The planets in our solar system do not travel in circular paths. Rather, their orbits are elliptical. The Sun is located at a fo

qwelly [4]

1. The distance between the perihelion and the aphelion is 116 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

3. The equation of the elliptical orbit of Mercury is $\frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1$

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Step-by-step explanation:

Let us revise the equation of the ellipse is

$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ , where the major axis is parallel to the x-axis

The length of the major axis is 2a
The coordinates of the vertices are (± a , 0)
The coordinates of the foci are (± c , 0) , where c² = a² - b²

∵ The Sun is located at a focus of the ellipse

∴ The sun located ate c

∵ The perihelion is the point in a planet’s orbit that is closest to the

Sun ( it is the endpoint of the major axis that is closest to the Sun )

∴ The perihelion is located at the vertex (a , 0)

∵ The closest Mercury comes to the Sun is about 46 million miles

∴ The distance between a and c is 46 million miles

∵ The aphelion is the point in the planet’s orbit that is furthest from

the Sun ( it is the endpoint of the major axis that is furthest from

the Sun )

∴ The aphelion is located at the vertex (-a , 0)

∵ The farthest Mercury travels from the Sun is about 70 million miles

∴ The distance from -a to c is 70 million miles

∴ The distance between the perihelion and the aphelion =

70 + 46 = 116 million miles

1. The distance between the perihelion and the aphelion is 116 million miles

∵ The distance between the perihelion and the aphelion is the

length of the major axis of the ellipse

∵ The length of the major axis is 2 a

∴ 2 a = 116

- Divide both sides by 2

∴ a = 58

∴ The distance from the center of Mercury’s elliptical orbit to the

closest end point to the sun is 58 million miles

∵ The distance between the sun and the closest endpoint is

46 million miles

∴ The distance from the center of Mercury’s elliptical orbit and

the Sun = 58 - 46 = 12 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

∵ The major axis runs horizontally

∴ The equation is $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$

∵ a = 58

∵ c is the distance from the center to the focus of the ellipse

∴ c = 12

∵ c² = a² - b²

∴ (12)² = (58)² - b²

- Add b² to both sides

∴ (12)² + b² = (58)²

- Subtract (12)² from both sides

∴ b² = (58)² - (12)² = 3220

- Substitute these values in the equation

∴ $\frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1$

3. The equation of the elliptical orbit of Mercury is $\frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1$

The eccentricity (e) of an ellipse is the ratio of the distance from the

center to the foci (c) and the distance from the center to the

vertices (a) ⇒ $e=\frac{c}{a}$

∵ c = 12

∵ a = 58

∴ $e=\frac{12}{58}$ = 0.207

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

If the eccentricity is zero, it is not squashed at all and so remains a circle.

If it is 1, it is completely squashed and looks like a line

∵ The eccentricity of the ellipse is 0.207

∵ This number is closed to zero than 1

∴ The shape of the ellipse is near to the shape of the circle

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Learn more:

You can learn more about conics section in brainly.com/question/4054269

#LearnwithBrainly

5 0

3 years ago

Give two ways to write each algebraic expression in words. 4+×

KATRIN_1 [288]

Answer:

the sum of 4 and a number

4 plus a number

4 0

3 years ago

A data set has a maximum of 84, a minimum of 34, a median of 52.5, an upper quartile of 64, and a lower quartile of 44. Which st

Akimi4 [234]

Answer:

A box and whiskers plot has a box whose endpoints are the interquartile range (25th percentile and 75th percentile), has a dividing line at the median, aka the 50th percentile, and whiskers that extend out to the minimum and the maximum of the data.

Let's sort the info for ease of reference:

min 34, lower quartile 44, median 52.5, upper quartile 64, max 84.

OK, let's go through the statements.

A. The box will go from 44 to 64.

The box goes from the lower quartile to the upper quartile, TRUE

B. A line dividing the box will be at 54.

There's no 54 mentioned at all, FALSE

C. The left whisker will go from 34 to 52.5.

The left whisker goes from the minimum to the lower quartile, 34 to 44 here, FALSE.

D. The right whisker will go from 44 to 84.

The right whisker goes from the upper quartile to the max, 64 to 84 here. FALSE

If this could help, please mark me brainliest! Have an awesome day too!

4 0

2 years ago