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Anettt [7]
3 years ago
10

Use mental math to find the sum of 432 + 250​

Mathematics
2 answers:
GrogVix [38]3 years ago
6 0

To start I would add 400 + 200, and that equals 600.

Then I would add 30 + 50, and that equals 80.

And then I have 2 left over.

600 + 80 = 680

Add the left over 2, so 680 + 2

680 + 2 = 682. Your answer is 682.

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
myrzilka [38]3 years ago
3 0

Answer: 682

Step-by-step explanation:

Add 432+250 (4+2 is 6 3+5 is 8 2+0 is 2) put the numbers together and get 682

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goldfiish [28.3K]

26-2\left(10-1\right)+\left(3+4\cdot 11\right)

26-(2)(9)+3+(4)(11)

26-18+3+(4)(11)

8+3+(4)(11)

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55

"55 is correct answer".

Hope this helps!

Thanks!

-Charlie

5 0
3 years ago
The simple interest on $2000 at 2% per annum for 3 months is
Jet001 [13]

Step-by-step explanation:

s.i= P×T×R/100

=2000×0.25×2/100

= 1000/100

= 10

8 0
2 years ago
Read 2 more answers
7. Which of the following statements is not
Amiraneli [1.4K]

Answer:

c

Step-by-step explanation:

it is because in (a) the square root of 112. is 10.58 which is in between 10 and 11

(B) the square root of 180 is 13.42 which is between 13&14

(c) the square root of 12 is 3.46 which is not between 4&5

6 0
3 years ago
Find the value of x.<br> (3x - 2)°<br> (10x - 11)<br> (3x + 1)<br> X=
Aleks [24]
Multiply the expressions.
90
x
3
−
129
x
2
+
13
x
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22
4 0
3 years ago
Read 2 more answers
Suppose that a study of elementary school students reports that the mean age at which children begin reading is 5.9 years with a
Bas_tet [7]

Answer:

5.9 years.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

Mean of the population is \mu = 5.9

If a sampling distribution is created using samples of the ages at which 69 children begin reading, what would be the mean of the sampling distribution of sample means?

By the Central Limit Theorem, the same population mean, of 5.9 years.

3 0
3 years ago
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