First expand the brackets by multiply everything in them by 2
2(3x-1)=
6x-2
then add the 4 and the 9 to -2 and you get
6x+11 so therefore its a
Answer:
I GOTCHU THE ANSWER IS -10
Step-by-step explanation:
Answer:The claim is correct
Explanation:Assume the given triangle ABCperimeter of triangle ABC = AB + BC + CA ............> I
Now, we have:D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> IIFrom I and II, we can prove that:perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:perimeter of midsegment triangle is half the perimeter of the original triangle.
Hope this helps :)
Answer:
ST = 4
Step-by-step explanation:
RS + ST = RT, substitute values
3x - 8 + x = 2x, that is
4x - 8 = 2x ( subtract 2x from both sides )
2x - 8 = 0 ( add 8 to both sides )
2x = 8 ( divide both sides by 2 )
x = 4
Thus ST = x = 4