Answer:
a) 4/27
b) 1/3
c) 6/27
Step-by-step explanation:
HI!
a)
The event A has only one member:
T T H
Therefore:
P(A) = P(T)P(T)P(H) = (2/3)(2/3)(1/3) = 4/27
b)
For event B, we are only interested in the last toss
x x H
Since the first two tosses are not important for event B they do not contribute to P(B)
P(B) = 1 * 1* P(H) = 1/3
c)
The following are elements of C:
H H T
H T H
T H H
Therefore:
P(C) = P(HHT) + P(HTH) + P(THH)
We can easily see that the probability of the three members is the sam:
P(HHT) = (1/3) (1/3) (2/3) = 2/27
P(HTH) = (1/3) (2/3) (1/3) = 2/27
P(THH) = (2/3) (1/3) (2/3) = 2/27
Therefore:
P(C) = 3 P(HHT) = 6/27
Using the normal distribution, the value that separates the highest 70% of the scores in a normal distribution from the lowest 30% is:
z = -0.52.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The value that separates the highest 70% of the scores in a normal distribution from the lowest 30% is is the 30th percentile, which is <u>Z with a p-value of -0.3,</u> hence z = -0.52.
More can be learned about the normal distribution at brainly.com/question/4079902
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The answer to this is -1/6
Decimal form: -0.16 (underline on the 6 which represents repeating number)
Hope this helped.
Your answer is the commutative property
Hope I helped
best of luck :)