Answer:
1) The alleles for homozygous brown hair will be BB.
2) The alleles for heterozygous brown hair will be Bb
3) Let's make a punnet square to check for the outcomes:
B b
B BB Bb
B BB Bb
4) The results from the punnet square depict that the phenotype of all the children produced will be brown hair.
5) The punnet square depicts that there will be a 50% probability of the child to carry the heterozygous genome (Bb) and there is also 50% probability for the child to carry homozygous dominant genome (BB).
Answer: Option E -- RNA Editing
Explanation:
It should be noted that, RNA editing can be defined as a molecular process via which some cells can make discrete changes to specific nucleotide sequences within an mRNA molecule after it has been generated by RNA polymerase. In addition, we have two major types of RNA editing with 1 being a C-to-U change catalyzed by cytidine deaminase that deaminates a cytidine base into a uridine base, e.g C-to-U editing is with the apolipoprotein B gene in humans. ApoB-100 is expressed in the liver and apoB-48 is expressed in the intestines. The B-100 form comprises of a CAA sequence that is edited to UAA, a stop codon, in the intestines.
This will make the other animals not have food because of the decline in rabbits which results in them dying
Answer:
1. Outer layer of cells = epidermis
2. Tube connecting the mouth to the stomach = esophagus
3. Iron compound in red blood cells = hemoglobin
4. The distal half of the small bowel = ileum
5. The middle part of the small bowel = jejunum
Explanation:
